>>134

②^3
=②(2-ω)③
=(2-ω)(2ω+3)④
=(2-ω)(2ω+3)√-7
=(-2ω^2+ω+6)√-7
=(3ω+8)√-7
=(-3√(-7)-3√21)/2+16√-7/2
=(13√(-7)-3√21)/2

⑥^3
=⑥(3+ω)⑤
=(3+ω)(-2ω+1)⑦
=(-2ω^2-5ω+3)⑦
=(-3ω+5)√5
=(3√(-7)+3√21)/2+10√-7/2
=(13√(-7)+3√21)/2

④=√(-7)
②=((13√(-7)/2-3√21)/2)^(1/3)
⑥=((13√(-7)/2+3√21)/2)^(1/3)

ζ7　-ζ7^6=1/3(④+　　②+　　⑥)
ζ7^2-ζ7^5=1/3(④+ω^2②+ω　⑥)
ζ7^4-ζ7^3=1/3(④+ω　②+ω^2⑥)