>>74
列挙なしで、6^10のうちの個数を計算
choose(n,r)はnからr個を選ぶ組み合わせの個数
C[n,r] やnCrと同じ
m1は1種類の個数
m2は2種類の個数
....

m1=choose(6,1)*(1^10) ; m1
m2=choose(6,2)*(2^10-2) ; m2
m3=choose(6,3)*(3^10-3-choose(3,2)*(2^10-2)) ; m3
m4=choose(6,4)*(4^10-4-choose(4,3)*(3^10-3)+choose(4,2)*(2^10-2))
m4
m5=choose(6,5)*(5^10-5-choose(5,4)*(4^10-4)+choose(5,3)*(3^10-3)-choose(5,2)*(2^10-2))
m5
m6=choose(6,6)*(6^10-6-choose(6,5)*(5^10-5)+choose(6,4)*(4^10-4)-choose(6,3)*(3^10-3)+choose(6,2)*(2^10-2))
m6