分からない問題はここに書いてね 472

>>676
>(ap+bq)^2-a^2p-b^2q=0
a^2(p^2-p)+2abpq+b^2(q^2-q)=0
(pq)^2-(p^2-p)(q^2-q)≧0
pq(pq-(p-1)(q-1))≧0
pq(p+q-1)≧0
(x,y)=(0,0),(1,0),(0,1),(p,q)
p=0,1,q=0,1,p+q=0,1 NG
p,q<0 NG
1-p<q<0 NG
1-q<p<0 NG
0<p,q,p+q<1 NG
(x,y)=(0,0),(1,0),(1,1),(p,q)
p=0,1,q=0,1,p-q=0,1 NG
p>1,q<0 NG
p<q<0 NG
1<p<q NG
0<q<p<1 NG