>>15
λ1 = a, λ2 = b, λ3 = c と置きなおす。

= (a-b)(b-c)(c-a) = 8√1509997 ≒ 9830.554816

c-b = 勍(8-a)/{2(6209-379a)},
c-a = 勍(b-8)/{2(6209-379b)},
b-a = 勍(c-8)/{2(379c-6209)},

a = 12 -b/2 -勍(b-8)/{4(6209-379b)} = 12 -c/2 -勍(c-8)/{4(379c-6209)},
b = 12 -a/2 -勍(8-a)/{4(6209-379a)} = 12 -c/2 +勍(c-8)/{4(379c-6209)},
c = 12 -a/2 +勍(8-a)/{4(6209-379a)} = 12 -b/2 +勍(b-8)/{4(6209-379b)},