慜>>696
>>697夋憸2偮栚丅
仮CAB佷仮CED傛傝丄
DE=3/2丄CE=7/2丄BE=8-7/2=9/2
B傪婲揰偵儊僱儔僂僗偺掕棟傛傝丄
(BE/EC)(CD/DA)(AF/FB)=1
(9/7)(4/3)(AF/AF+3)=1
12AF=7(AF+3)
AF=21/5
摨條偵F傪婲揰偵儊僱儔僂僗偺掕棟傛傝丄
(FA/AB)(BC/CE)(ED/DF)=1
{(21/5)/3}{8/(7/2)}{(3/2)/DF}=1
21=5DF
DF=24/5
暘偐傜側偄栤戣偼偙偙偵彂偄偰偹453
仭 偙偺僗儗僢僪偼夁嫀儘僌憅屔偵奿擺偝傟偰偄傑偡
705僀僫 仧/7jUdUKiSM
2019/06/25(壩) 01:28:23.67ID:H5bk105E仭 偙偺僗儗僢僪偼夁嫀儘僌憅屔偵奿擺偝傟偰偄傑偡
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